Quote from Sagaris
Quote from chineserider
Basically, you have [integral]1/(1+sinx) dx
Then you separate that into [integral]1/1 + [integral]1/sinx (which is cscx)
Then you separate that into [integral]1/1 + [integral]1/sinx (which is cscx)
Fractions don't work that way.
Integral of dx/(1+sinx) is the same as dx * 1/(1+sinx). I have never seen people prove it otherwise. You cannot have a dx on the denominator, but dx on the numerator is acceptable.
Edit: Sorry. Wasn't paying attention to the parenthesis there.
Last edited by chineserider at 12:45 am, Oct 31 2011
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