Most of the people who can help with physics, plus some others. Again, give us the questions and someone will go for it. (And hopefully try to avoid the drama a simple physics question caused.)

Hey, that's not what i did !!
O_O i tried to keep this from afftecting your ego, well, atleast i tried
These are what you said, right ?
I said that this is half correct ( one of my effort to make it sound less harsh,erm, my friends woudn't use that word if they see this) Even from the most basic context, there are cases that the magnitude of a velocity vector is not speed, at all. The best terms to conceptualize the relationship between them are "distance traveled","displacement", and "instantaneous".

This is wrong, i tried to give out the hint, but i was disappointed. And i was serious when i said you should do research on this if you want to discuss. Why would i try to flame you, lol But look at how this has turned out. O_O
In a zigzag trajectory, the object must have acceleration, i never disagree with that -_- And there's nothing wrong if an object with such motion has constant speed. When the acceleration vector changes the velocity vector, its speed can be constant.
A simple example, a ball zigzags when it bounces back and forth elastically between 2 parallel walls. Its velocity does change (due to elastic collision), its speed doesn't. And you tell me what is the acc ? how does it affect the ball's motion ? (just asking for fun)
The average speed = distance traveled / time taken -_-
And the distance traveled is different from the displacement (the change in position)
O_O you said it all, read what i post again if you like.
You are being over sensitive...
I'm just not sure of the system in US, and i haven't even mention about my country's. Plus i don't follow the general educational system of my country, well, not that i care my curriculum is a bit different.

O_O



And i was trying to optimize the answer Come to think of it, if there's no argument, there's no optimization, and i don't feel sorry, not one bit.
Perhaps i m a self righteous troll


PS. Uncivilized, lol

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Silencer and Box Box-take it to pm.

You guys are getting into far more detail than MasamiAkane needs-seriously one half right answer would have been fine 'cause in physics 101 it doesn't matter so much which option you choose. The solutions usually are such that as long as she uses the formula in her book for speed, she'll be fine. I also think you scared the poor girl off from asking any more questions.

Next post directed at each other will be immediately deleted.

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ANYWAY......

So, I was doing some review problems on a test, and I got them wrong. Only, I'm pretty sure I did it right, so it might just because my teacher had his 10 year old kid grade the paper AGAIN. (I hate my teacher)

(Basically, I just want you guys to check if these are right, so I can go complain to him about it.)

So like, a problem was x^2 + 5x =0. I put the answer as -5.

Also, another was was x^2 + x = 56. I put the answer x=7.

Or one was factoring, as was like,
8x^2 + 8x + 2, and I put the factor as (4x+2)(2x+1)

Another one was 4x^2 = 81, and I put the answer as 9/2

and x^2 + 18x +81 = 0 (Factoring), I put (-18,-81) as the answer.

Last edited by Dragonfiremule at 4:21 pm, Jan 4 2010

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The complete answer is 9/2 and -9/2

Notice this is a positive/negative answer combination.



(x+9)^2=0

So x+9=0

x=-9




Answer is x=7, x=-8



Answer x=0, x=-5



deduce down to 4x^2+4x+1=0 so the final factor form is (2x+1)^2

Last edited by BoxBox at 4:40 pm, Jan 4 2010

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Gay book discussion thread

Damn. I was hoping it was the teachers fault.
What about the rest?


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Dragonfiremule: I haven't done algebra for a long time, but the following is what I thought the answer should be.

x^2 + 5x =0 --> x(x+5)=0 --->therefore, x =0 and x=-5

x^2 + x = 56 --> x^2 + x -56 = 0 -->(x-7)(x+8)=0 --> therefore x=7 and x=-8

8x^2 + 8x + 2 --> 2(4x^2 +4x +1) --> 2(2x+1)(2x+1) or 2(2x+1)^2

Yep, exactly. It's strange though, I would have thought the teacher might accept his/her 8x^2 + 8x + 2 answer. I guess that teacher is particularly b-tchy....

I would still go to the teacher to complain about that problem though.

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Gay book discussion thread

First one, answers are 0 and -5.

Second one, -8 and 7.

Third one, 8(x+1/2)^2.
You have to isolate x^2 here, so:
8x^2+8x+2=
8(x^2+x+1/4)=
8(x+1/2)(x+1/2)=
8(x+1/2)^2
(I think, last time I did this stuff was ages ago ).

Fourth one, 9/2 and -9/2.


Remember that second grade equations always have two solutions when b^2-4ac > 0.


Edit: Well, someone already answered but still I'm leaving here the post


Last edited by reid1 at 4:51 pm, Jan 4 2010

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Thanks guys. I get why he marked \them wrong. I forgot to put the second part of the answer or didn't simplify all the way. Thanks for the help. (Boxbox, I'm a she.)


Oh, I have one last question.

Its factoring.

(x-4)^2=9 so I did

(x-4)(x-4)=9

x^2 - 8x - 16 = 9
x^2-8x-25=0

So to solve it, I would have to factor that out more, but I can't seem to do so, so I think it may be prime. Is this correct? And would that be the answer?


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If I still remember something...

(x-4)^2=9

x^2-8x+16=9
x^2-8x+7=0
X1=7
X2=-1

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you would be my rainbow in shades of grey.

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If I had a fantasy self, it'd be a tentacle monster.

OH! Thanks. I didn't realize I had not turned the 16 into a positive 16. Thanks.

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NP.
I like the algebra I can solve.
I think I screwed up there though.
It's -7, -1
^^;;;;

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Hrodulf and Bjornolfr, you will not be forgotten.

And if the world were black and white,
you would be my rainbow in shades of grey.

Click 'n Play!

If I had a fantasy self, it'd be a tentacle monster.

The 7 is correct, but I don't know about the -1.

-1^2 - 8(-1) +7 = 0

1 + 8 + 7 =/= 0

A regular 1 works though.

1 + -8 + 7 = 0

Unless you do the opposite? I can't remember...

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