@@
Okay.
SOO. My teacher told me the answer.
He said it was a redox reaction.
@@

And the answer...I wrote it down somewhere...5Ag...something...
:<

♪MONSTARR~ will eat all your cookies and steal your bishies~♪ Φ_Φ

oh um.. i forgot my dam text book and uh well my essay is due on monday >.> so was wondering if anyone can give me pros on the protestants reformation.. martin luther john hus.. whycliff.. examples would be darn useful please and thank yoU!
😀
mad typist
lost on the research

= Stress is what we Live FOR =

/===CODE OF CONDUCT===~\
|A Life For A Life|

Quote from StarlightDreams

<.<
had to search for this thread

Ag (s) + HNO−3 (aq) -> H−2 (g) + NO + AgNO−3 (aq)

− = Subscript.

Someone please balance it for me. D:

I notice this thread too late. One doesn't have to know about the change of oxidation state ( happens in the so called redox reactions) to solve this. Pure algebra with a small hint that we are in aqueous solution are what you need :

5Ag(s)+6HNO-3(aq) -> H-2(g)+NO+5AgNO-3(aq)+2 H-2O
( the will always be collision with water molecules )

post this in case someone still cares.

[img]http://i148.photobucket.com/albums/s28/joshua_569/allstarssilencer4do.png[/img]

Quote from silencer

Quote from StarlightDreams

<.<
had to search for this thread

Ag (s) + HNO−3 (aq) -> H−2 (g) + NO + AgNO−3 (aq)

− = Subscript.

Someone please balance it for me. D:

I notice this thread too late. One doesn't have to know about the change of oxidation state ( happens in the so called redox reactions) to solve this. Pure algebra with a small hint that we are in aqueous solution are what you need :

Yea...

Quote from dictionary.com

stoichiometry [stoi-kee-om-i-tree]
–noun
the calculation of the quantities of chemical elements or compounds involved in chemical reactions.

Hurray Math

[color=#ff0000]"“That's the difference between me and the rest of the world!
Happiness isn't good enough for me! I demand euphoria!” "[/color]

;_;
I didn't know!
I didn't get the extra credit either. Evil teacher. D:

♪MONSTARR~ will eat all your cookies and steal your bishies~♪ Φ_Φ

i have 2 pratical work
and 2 exams tomorow an i didnt do shit this weekend!!!
im so screwed... 🤢

v = [x,y,z]
[2,-3,1] x v = [1,0,2]
Solve for x, y and z. (This is the cross product of 2 vectors)

I don't think it works but I'd appreciate it if someone could confirm that for me or tell me how to solve it.

[img]http://piro.pirocast.net/badge/521996.png[/img]

you know what is cross product and what is scalar product right ?

u = [2,-3,1]
v = [x,y,z]
w = [1,0,2]

u x v = w means u and w must be perpendicular to each other so that v exists, while, clearly, they aren't,

you can check by scalar product and can find the angle between them if you want to.

[img]http://i148.photobucket.com/albums/s28/joshua_569/allstarssilencer4do.png[/img]

wow I didn't know this existed! I guess I have one.

Given r(x)= (8x^10) - (2x^5)
rewrite r(x) as a composition of 3 functions.
Find:
f(x)
g(x)
h(x)
such that (f) o (g) o (h) = r(x)

The river of life is magnificent and dangerous.

Quote from Althaea

Given r(x)= (8x^10) - (2x^5)

assuming that r(x) = f(g(h(x)))
8x^10 factors out to 24x^10 -> 22x^5*2x^5

some factoring rules:
x^a = x^b+c, a=b+c
jx =klx, j=kl

Thanks! makes much more sense now and I didn't learn those factoring rules yet.

The river of life is magnificent and dangerous.

Yeah, though there are infinitely many ways to find f(x), g(x) and h(x) in that case, most of them require math at high school level though.

[img]http://i148.photobucket.com/albums/s28/joshua_569/allstarssilencer4do.png[/img]

Quote from Vildur

v = [x,y,z]
[2,-3,1] x v = [1,0,2]
Solve for x, y and z. (This is the cross product of 2 vectors)

I don't think it works but I'd appreciate it if someone could confirm that for me or tell me how to solve it.

Well you try the determinant of the equation so you have the matrix

( i j k )
( 2 -3 -1 )
( x y z )
If you find the determinants you end up with

i(-3z - y) - j(2z - x) + k(2y + 3x)

you know that the value for i = 1 and j = 0 and k = 2

so you have 3 equations
-3z -y = 1
-2z + x = 0
2y + 3x = 2

Then you solve using an augmented matrix

( 0 -1 -3 ] 1 )
( 1 0 -2 ] 0 )
( 3 2 0 ] 2 ) Let Row 3 be equation to (Row 3) - (Row 2)*3

( 0 -1 -3 ] 1 )
( 1 0 -2 ] 0 )
( 0 2 6 ] 2 ) Let Row 3 be equation to (Row 3) + (Row 1)*2

( 0 -1 -3 ] 1 )
( 1 0 -2 ] 0 )
( 0 0 0 ] 4 )

There is an infinite number of solution so I'm really confused about the question now... lol

I'm doing the working in my head so check out the working out, I haven't done this for about 2years now and a bit rusty lol

Do not feed the trolls
[img]http://img517.imageshack.us/img517/5526/fireproofbyevilbug.jpg[/img]

ive got another problem i need help on and its on functions again!

f(x)=ax+b
inverse of f(x)=bx+a

with a,b real, what is the value of a+b?

The river of life is magnificent and dangerous.

f(x)=ax+b
to find f^-1(x):
y = ax+b
x = ay+b
y = (x-b)/a
f^-1(x) = (x-b)/a
but : f^-1(x) = bx+a
so
x/a = bx and -b/a = a
b = 1/a and b = -a²
1/a = -a²
a(1/a) = a(-a²)
1 = -a³

a = -1
b = 1/-1 = -1

a + b = -2

[img]http://i593.photobucket.com/albums/tt14/12douces/000f-g.jpg[/img]