An hour is plenty of time to copy off someone who has done it.

[quote=Dr. Love] ^ that's too fast~ I have no clue at all, but I searched for a sec.

The soft flesh of a banana provides a ready source of DNA?

Other related links:

1
2

Sorry. :'[ [/quote]

N'aww , no need to apologize. 😛
Although I already saw those sites before, I didn't know anything about the banana's flesh lol. 😀

Thanks so much!~ 😃

Quote from Sagaris

An hour is plenty of time to copy off someone who has done it.

Hahaha, mind you that is IF I can find somone willing to... 😐
But thanks. 🙂

[url=http:////www.mangaupdates.com/showtopic.php?tid=42718][img]http://i366.photobucket.com/albums/oo105/CatzCradle64/Avis-Sigs/FunghiPower_zps2a00ba56copy_zpsfc03990e.png[/img][/url]

I want a 60% Bleach Solution to clean windows. I have 3.6 gallons of a 50% bleach solution and a bottle of bleach solution marked as 75%. I'll add to the 50% container. How much of the 75% solution should I add?

I need help with this Math problem. I realize that this is probably a stupid question... I tried to bold the important parts >_>; Any help would be greatly appreciated... Thanks!

Edit: Ok, thanks for the help, Sagaris and xxxIllusionxxx! I'll see how these work out~

[img]http://www.nodiatis.com/pub/21.jpg[/img]

Basically you just split the solution into bleach and water. Since you start out with 3.6 of 50%, you have 1.8 of each, then you add the 75% solution until you get a 60% solution. You can show this by:

(1.8+0.75x)/(1.8+0.25x) = 0.60/0.40 where it's sort of a ratio. Just solve that and you're finished.

Or I'm horribly wrong.

Sagaris might be right, but the way I figured was easiest was to break the whole equation into ratios and solve for x. So: 3.6 / 50 + x / 75 = (x+3.6) / 60 ---> 21.6/300+ 4x/300= (5x+18)/300 ---> 21.6 +4x= 5x+18 ----> 21.6= x+ 18 ---->x= 3.6

I dont know if they break down to the same answer or not and mine might be wrong, but I figured I'd give it a shot anyway

( (3.6/2) + (0.75x) ) / 3.6 + x = 60 /100

....

x = 2.4

or am i really really wrong? O_o

Quote from MadameRed

( (3.6/2) + (0.75x) ) / 3.6 + x = 60 /100

....

x = 2.4

or am i really really wrong? O_o

I'll have to agree with Madame Red, this is what I got

(0.53.6) + (0.75x) = (0.6(3.6+x))
1.8 + 0.75x = 2.16 + 0.6x
0.15x = 0.36
x = 2.4gallons.

New found volume is now 2.4+3.6gallons which is 6gallons.
Substitute in the value you get (0.53.6)+(0.752.4) = 3.6gallons of bleach
3.6/6 = 0.6, we have a 6gallon 60% bleach solution.

When I do calculations like these I just do,
50%(Initial volume) + 75%(additional volume) = 60%(Initial+final volume)
It saves from using ratios and gives a straight forward linear equation.

Do not feed the trolls
[img]http://img517.imageshack.us/img517/5526/fireproofbyevilbug.jpg[/img]

Does anyone know the iodine clock reaction for bisulfite (HSO3 -) and iodate (IO3 -) with hydrogen ion (H+) catalyst? I'm googling, but all I get is iodine clock with hydrogen peroxide.

Also if a have a rate vs initial concentration graph that looks like a square root function, what did I do wrong?

5 HSO3- + 2 IO3- => I2 + 5SO4(2-) + H2O + 3H+

If it's a lab, then nothing is wrong. Your results simply did match what was predicted and you can blame various sources of error.

5HSO3-(aq) + 2IO3(-)(aq) ------> I2(aq) + 5SO4(2-)(aq) + 3H+(aq) + H2O(l)

Something like this?

Edit: Looks like someone beat me to it lol

Do not feed the trolls
[img]http://img517.imageshack.us/img517/5526/fireproofbyevilbug.jpg[/img]

Quote from Sagaris

5 HSO3- + 2 IO3- => I2 + 5SO4(2-) + H2O + 3H+

Thank you but I meant is there a bunch of formalae that show all the steps of the iodine clock reaction like
IO3- + 5I- + 6H+ → 3I2 + 3H2O
I2 + HSO3- + H2O → 2I- + HSO4- + 2H+
sort of thing but with a hydrogen catalyst?...the hydrogen catalyst is kinda important b/c i makes everything go faster/activation energy lower for 1st rxn, which is what i'm trying to find.

Reaction rate mechanisms? The first step is rate determining.
Then I have no idea.

Yeah...something like that...
I would just like to know which is rate determining with a catalyst really

Edit: Nevermind, it's handed in

Can someone show me the steps to find the antiderivative of 1/(1 + x^2)?

[img]http://i.imgur.com/OkzQ4.png[/img]

Quote from daisukidesuyo

Can someone show me the steps to find the antiderivative of 1/(1 + x^2)?

This is usually memorized rather than proof, the proof is very tedious.
Here is a site called Wolfram Online Integrator. This free site allows integration[anti-derivative]. It is one of the best site to use, especially for college students.
Just copy and past what you wrote and then let the machine do it for you.

Someone on internet did it very nicely step by step as you requested.
Answer is Tan-1(x) or Arctan

Here is the extra information.

Gay book discussion thread

Quote from you_no_see_me_

this is not about cannibalism...please get back on topic

Quote from Toto

I think it is exactly the topic. I see nothing wrong.