@_@
Okay.
SOO. My teacher told me the answer.
He said it was a redox reaction.
@_@
And the answer...I wrote it down somewhere...5Ag...something...
:<
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Post #325950
Lowly Member
Member
3:08 pm, Oct 6 2009
Posts: 3888
Post #328370
Member
6:37 pm, Oct 17 2009
Posts: 536
oh um.. i forgot my dam text book and uh well my essay is due on monday >.> so was wondering if anyone can give me pros on the protestants reformation.. martin luther john hus.. whycliff.. examples would be darn useful please and thank yoU!
mad typist
lost on the research
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~= Stress is what we Live FOR =~
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mad typist
lost on the research
________________
~= Stress is what we Live FOR =~
/===~CODE OF CONDUCT~===~\
|________A Life For A Life________|
The last Blood Elf
Member
12:31 am, Oct 18 2009
Posts: 200
Quote from StarlightDreams
<.<
*had to search for this thread*
Ag (s) + HNO−3 (aq) -> H−2 (g) + NO + AgNO−3 (aq)
− = Subscript.
Someone please balance it for me. D:
*had to search for this thread*
Ag (s) + HNO−3 (aq) -> H−2 (g) + NO + AgNO−3 (aq)
− = Subscript.
Someone please balance it for me. D:
I notice this thread too late. One doesn't have to know about the change of oxidation state ( happens in the so called redox reactions) to solve this. Pure algebra with a small hint that we are in aqueous solution are what you need :
5Ag(s)+6HNO-3(aq) -> H-2(g)+NO+5AgNO-3(aq)+2 H-2O
( the will always be collision with water molecules )
post this in case someone still cares.
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Quote from silencer
Quote from StarlightDreams
<.<
*had to search for this thread*
Ag (s) + HNO−3 (aq) -> H−2 (g) + NO + AgNO−3 (aq)
− = Subscript.
Someone please balance it for me. D:
*had to search for this thread*
Ag (s) + HNO−3 (aq) -> H−2 (g) + NO + AgNO−3 (aq)
− = Subscript.
Someone please balance it for me. D:
I notice this thread too late. One doesn't have to know about the change of oxidation state ( happens in the so called redox reactions) to solve this. Pure algebra with a small hint that we are in aqueous solution are what you need :
Yea...
Quote from dictionary.com
stoichiometry [stoi-kee-om-i-tree]
–noun
the calculation of the quantities of chemical elements or compounds involved in chemical reactions.
–noun
the calculation of the quantities of chemical elements or compounds involved in chemical reactions.
Hurray Math
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Post #328739
Lowly Member
Member
9:43 pm, Oct 18 2009
Posts: 3888
;_;
I didn't know!
I didn't get the extra credit either. Evil teacher. D:
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♪MONSTARR~ will eat all your cookies and steal your bishies~♪ Φ_Φ
I didn't know!
I didn't get the extra credit either. Evil teacher. D:
________________
♪MONSTARR~ will eat all your cookies and steal your bishies~♪ Φ_Φ
Member
9:54 pm, Oct 18 2009
Posts: 258
9:54 pm, Oct 18 2009
Posts: 258
i have 2 pratical work
and 2 exams tomorow an i didnt do shit this weekend!!!
im so screwed...
and 2 exams tomorow an i didnt do shit this weekend!!!
im so screwed...
Dungeon Master
Member
6:36 pm, Oct 27 2009
Posts: 38
The last Blood Elf
Member
9:15 pm, Oct 28 2009
Posts: 200
you know what is cross product and what is scalar product right ?
u = [2,-3,1]
v = [x,y,z]
w = [1,0,2]
u x v = w means u and w must be perpendicular to each other so that v exists, while, clearly, they aren't,
you can check by scalar product and can find the angle between them if you want to.
________________
u = [2,-3,1]
v = [x,y,z]
w = [1,0,2]
u x v = w means u and w must be perpendicular to each other so that v exists, while, clearly, they aren't,
you can check by scalar product and can find the angle between them if you want to.
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Tea Leaf
Member
7:05 pm, Oct 29 2009
Posts: 192
wow I didn't know this existed! I guess I have one.
Given r(x)= (8x^10) - (2x^5)
rewrite r(x) as a composition of 3 functions.
Find:
f(x)
g(x)
h(x)
such that (f) o (g) o (h) = r(x)
________________
The river of life is magnificent and dangerous.
Given r(x)= (8x^10) - (2x^5)
rewrite r(x) as a composition of 3 functions.
Find:
f(x)
g(x)
h(x)
such that (f) o (g) o (h) = r(x)
________________
The river of life is magnificent and dangerous.
Member
7:21 pm, Oct 29 2009
Posts: 510
Quote from Althaea
Given r(x)= (8x^10) - (2x^5)
assuming that r(x) = f(g(h(x)))
8x^10 factors out to 2*4x^10 -> 2*2x^5*2x^5
some factoring rules:
x^a = x^b+c, a=b+c
j*x =k*l*x, j=k*l
Tea Leaf
Member
7:40 pm, Oct 29 2009
Posts: 192
Thanks! makes much more sense now and I didn't learn those factoring rules yet.
________________
The river of life is magnificent and dangerous.
________________
The river of life is magnificent and dangerous.
The last Blood Elf
Member
9:18 pm, Oct 29 2009
Posts: 200
Yeah, though there are infinitely many ways to find f(x), g(x) and h(x) in that case, most of them require math at high school level though.
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________________
Wall-o-text
Member
4:01 pm, Oct 30 2009
Posts: 367
Quote from Vildur
v = [x,y,z]
[2,-3,1] x v = [1,0,2]
Solve for x, y and z. (This is the cross product of 2 vectors)
I don't think it works but I'd appreciate it if someone could confirm that for me or tell me how to solve it.
[2,-3,1] x v = [1,0,2]
Solve for x, y and z. (This is the cross product of 2 vectors)
I don't think it works but I'd appreciate it if someone could confirm that for me or tell me how to solve it.
Well you try the determinant of the equation so you have the matrix
( i j k )
( 2 -3 -1 )
( x y z )
If you find the determinants you end up with
i(-3z - y) - j(2z - x) + k(2y + 3x)
you know that the value for i = 1 and j = 0 and k = 2
so you have 3 equations
-3z -y = 1
-2z + x = 0
2y + 3x = 2
Then you solve using an augmented matrix
( 0 -1 -3 ] 1 )
( 1 0 -2 ] 0 )
( 3 2 0 ] 2 ) Let Row 3 be equation to (Row 3) - (Row 2)*3
( 0 -1 -3 ] 1 )
( 1 0 -2 ] 0 )
( 0 2 6 ] 2 ) Let Row 3 be equation to (Row 3) + (Row 1)*2
( 0 -1 -3 ] 1 )
( 1 0 -2 ] 0 )
( 0 0 0 ] 4 )
There is an infinite number of solution so I'm really confused about the question now... lol
I'm doing the working in my head so check out the working out, I haven't done this for about 2years now and a bit rusty lol
Last edited by Noobsrus at 4:12 pm, Oct 30 2009
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Do not feed the trolls
Tea Leaf
Member
10:23 pm, Nov 3 2009
Posts: 192
ive got another problem i need help on and its on functions again!
f(x)=ax+b
inverse of f(x)=bx+a
with a,b real, what is the value of a+b?
________________
The river of life is magnificent and dangerous.
f(x)=ax+b
inverse of f(x)=bx+a
with a,b real, what is the value of a+b?
________________
The river of life is magnificent and dangerous.
Member
6:29 am, Nov 4 2009
Posts: 157
f(x)=ax+b
to find f^-1(x):
y = ax+b
x = ay+b
y = (x-b)/a
f^-1(x) = (x-b)/a
but : f^-1(x) = bx+a
so
x/a = bx and -b/a = a
b = 1/a and b = -a²
1/a = -a²
a(1/a) = a(-a²)
1 = -a³
a = -1
b = 1/-1 = -1
------
a + b = -2
________________
to find f^-1(x):
y = ax+b
x = ay+b
y = (x-b)/a
f^-1(x) = (x-b)/a
but : f^-1(x) = bx+a
so
x/a = bx and -b/a = a
b = 1/a and b = -a²
1/a = -a²
a(1/a) = a(-a²)
1 = -a³
a = -1
b = 1/-1 = -1
------
a + b = -2
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