Quote from Noobsrus
( i j k )
( 2 -3 -1 )
( x y z )
If you find the determinants you end up with
i(-3z - y) - j(2z - x) + k(2y + 3x)
....
There is an infinite number of solution so I'm really confused about the question now... lol
....
( 2 -3 -1 )
( x y z )
If you find the determinants you end up with
i(-3z - y) - j(2z - x) + k(2y + 3x)
....
There is an infinite number of solution so I'm really confused about the question now... lol
....
You are solving simultaneous equations ( a middle school problem) using matrix O_O and
do it wrong from the beginning O__O
plus, you are trying to find a nonexistent vector O____O
And the solution above is okay, not really pretty though:
f(x) = ax+b
inv f(x) = bx+a
The definition of inverse function: f(inv(f(x)) = x for every value of x
thus a(bx+a)+b = x or (ab-1)x + b +a^2 = 0 for every value of x
---> ab-1=0 and b+a^2=0 ----> a=b=-1
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